douzhangjian1505 2017-12-16 19:28
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Laravel显示数据

I'm new with Laravel or any MVC. I created the models, I create the route from web.php, I created the view with Blade, I created the controller and fetched all the data from a single model. Now, I want to make a join or something similar.

I want to get something this: Name | Section name | Status.

In my user Model I have: ID | Name | SectionID | Status

In my sections Model I have: ID | SectionID | Active

Currently I created the controller like this:

public function show($name)
{
    if(User::where('name', '=', $name)->exists())
    {
        return view('profile', ['user'=>User::where('name', $name)->first()]);

    }
    else
    {
        return 'User not found';
    } 
}

And in my Blade I'm getting content like this: {{ $user->name }}

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  • doukesou4452 2017-12-16 19:45
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    Hmm you have to define the relationship between user and section model. Please check this thread for how to work with relationships in laravel Laravel Eloquent Relationships.

    Then whenever you get the user you can load any relationship that its defined on User model.

    In your case you are performing two unecessary database calls, so I would suggest you to check out DRY principle.

    Lets say in User has one Section you define the relationship in User model like so:

    public function sections(){
    
      return $this->hasOne(Section::class);
    
    }
    

    Then the reverse relationship from section model:

    public function user(){
    
      return $this->belongsTo(User::class);
    
    }
    

    So now your method in controller might look something along the lines of this:

    public function show($name){
    
       return view('profile', ['user'=>User::with('sections')->where('name', $name)->firstOrFail()]);
    
    }
    

    This way you eagerload the sections that are tied to that user, for more about Laravel eagerloading

    Then in the blade you can access any of the attributes from user or section model.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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