dongshadu4498 2009-04-02 22:32
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非常基本的嵌套php

I am trying to write a very simple statement that will make it so that, if users of my blog don't have a gravatar, an image chosen randomly will appear. The way it works now is like this:

 <?php echo get_avatar( $comment, $size = '78', $default = '/images/noavatar2.gif' );  ?>

this will give me a random number:

echo(rand(1,10)

I want to echo the random number between "noavatar" and ".gif" but I can't seem to figure out how to do it. Any help would be appreciated.

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  • duanhe6799 2009-04-02 22:34
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    Try this:

    <?php echo get_avatar( $comment, $size = '78', $default = '/images/noavatar' . rand(1,10) . '.gif' ); ?>

    This uses a language feature called string concatenation; for more information on how this works in PHP: http://www.phpf1.com/tutorial/php-string-concatenation.html

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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