在xampp下的php中的命名空间

Question

I am working with php under xampp.

In my C:\xampp\htdocs\AppLib1\lib1.php

<?php
// application library 1 i.e. lib1.php
namespace AppLib1;

const MYCONST = 'AppLib1MYCONST';

function MyFunction() {
    return __FUNCTION__;
}

class MyClass {
    static function WhoAmI() {
        return __METHOD__;
    }
}
?>

and in my C:\xampp\htdocs\myapp.php

<?php
//myapp.php

header('Content-type: text/plain');
include_once ('lib1.php');

echo AppLib1MYCONST . "n";
echo AppLib1MyFunction() . "n";
echo AppLib1MyClass::WhoAmI() . "n";
?>

now when i am running myapp.php locally, I am getting Fatal Error

Warning: require_once(lib1.php): failed to open stream: No such file or directory in C:\xampp\htdocs\myapp.php on line 3

Fatal error: require_once(): Failed opening required 'lib1.php' (include_path='.;C:\xampp\php\PEAR') in C:\xampp\htdocs\myapp.php on line 3

Can some explain me how to use function, class, constant from lib1.php

output should be: AppLib1MYCONST AppLib1MyFunction AppLib1MyClass::WhoAmI

I Know Name collision problems can be solved with namespaces.

Answer 1

I believe you need to call it like this:

echo AppLib1\MYCONST . "n";
echo AppLib1\MyFunction() . "n";
echo AppLib1\MyClass::WhoAmI() . "n";