dongmei9508 2016-05-24 06:30
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php ldap检索dn的值

I'm trying below code to get the value as ou=grp1 from

dn: uid=john,ou=grp1,ou=people,dc=site,dc=com , but not understanding how to retrieve.

here is the code:

<?php

function pairstr2Arr ($str, $separator='=', $delim=',') {
    $elems = explode($delim, $str);
    foreach( $elems as $elem => $val ) {
        $val = trim($val);
        $nameVal[] = explode($separator, $val);
        $arr[trim(strtolower($nameVal[$elem][0]))] = trim($nameVal[$elem][1]);
    }
        return $arr;
}

//  Example usage:
$string = 'uid=john,ou=grp1,ou=people,dc=site,dc=com';
$array = pairstr2Arr($string);

echo '<pre>';
print_r($array);
echo '</pre>';

?>

output:

<pre>Array
(
    [uid] => john
    [ou] => people //here I want to get output ou=grp1,how?
    [dc] => com
)
</pre>

find output here: https://ideone.com/rE6eaH

  • 写回答

1条回答 默认 最新

  • douchen2595 2016-05-24 06:59
    关注

    Because of ou and dc might have multiple values, you should store those values in array. Thanks to that you can have easy access to data. Check out this code:

    <?php
    
    function pairstr2Arr ($str, $separator='=', $delim=',') {
        $elems = explode($delim, $str);
    
        $arr = array();
        foreach( $elems as $elem => $val ) {
            $val = trim($val);
            $tempArray = explode($separator, $val);
    
            if(!isset($arr[trim($tempArray[0])]))
                $arr[trim($tempArray[0])] = '';
    
            $arr[trim($tempArray[0])] .= $tempArray[1].';'; 
        }
    
        foreach($arr as $key => $value)
        {
            $explodedValue = explode(';', $value);
            if(count($explodedValue) > 2)
            {
                $arr[$key] = $explodedValue;
                unset($arr[$key][count($explodedValue) - 1]);
            }
            else
                $arr[$key] = substr($arr[$key], 0, -1);
        }
        return $arr;
    }
    
    //  Example usage:
    $string = 'uid=john,ou=grp1,ou=people,dc=site,dc=com';
    $array = pairstr2Arr($string);
    
    echo '<pre>';
    print_r($array);
    echo '</pre>';
    
    ?>
    

    Result is:

    Array
    (
        [uid] => john
        [ou] => Array
            (
                [0] => grp1
                [1] => people
            )
    
        [dc] => Array
            (
                [0] => site
                [1] => com
            )
    )
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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