dps43378 2015-02-26 10:36 采纳率: 0%
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两个提交相同表单的按钮

Lets says that I have form and in the end I have 2 buttons

1 - send test form

2 - send live form

both send the same form. How can I send parameter to the server so I will know if its test or live?

Thanks

<form method='post' action='index.php?page=mailing&amp;campID=<?PHP echo $_GET['campID'] ?>&amp;act=<?PHP echo $actType ?>' id="Form" >     
    <table class="sort">
        <tr>
            <td>email address</td>
            <td><input type="text" name="emailTest" value="<?PHP echo $user_details['email'] ?>" /></td>
        </tr>
        <tr>
            <td></td>
            <td><a href="#" class="button3d" onClick="document.getElementById('Form').submit()">send test</a></td>
            <td><a href="#" class="button3d" onClick="document.getElementById('Form').submit()">send live</a></td>
        </tr>
    </table>
</form>
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  • dsdapobp26141 2015-02-26 10:42
    关注

    Just check in php if 'submit' field is 'test' or 'live'.

    <form method='post' action='' id="Form" >     
        <table class="sort">
            <tr>
                <td>email address</td>
                <td><input type="text" name="emailTest" value="" /></td>
            </tr>
            <tr>
                <td></td>
                <td><button type="submit" name="submit" value="test">Test</button></td>
                <td><button type="submit" name="submit" value="live">Live</button></td>
            </tr>
        </table>
    </form>
    
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