理解include_path输出PHP

Question

I need help in understanding include_path and where it is set. When I echo include path this is what I see:

.:/Applications/XAMPP/xamppfiles/lib/php

From what I understand there are two paths currently in the include_path separated by colon. First one is the

'.' which indicates the current directory

and the second one is the path

'/Applications/XAMPP/xamppfiles/lib/php'

So my questions are:

1) Is the above understanding correct?
2) Where is the include_path set because I looked at my php.ini file  in /Applications/XAMPP/xamppfiles/etc but I couldn't find this being mentioned in the file

This is what my php.ini had and the same seems to be commented:

; UNIX: "/path1:/path2"
;include_path = ".:/php/includes"

Also including my phpinfo output

Configuration File (php.ini) Path   /Applications/XAMPP/xamppfiles/etc
Loaded Configuration File   /Applications/XAMPP/xamppfiles/etc/php.ini
Scan this dir for additional .ini files     (none)
Additional .ini files parsed    (none) 

Answer 1

1. Yes
2. In php.ini like you thought. Use phpinfo(); to see what configuration files gets loaded. There could be additional php.ini files or this is not correct php.ini file loaded. Also, it can be easily changed from PHP code, .htaccess files etc.

In phpinfo() output, search for Loaded Configuration File and Additional .ini files parsed.

From command line, use command php -i to get php info.