dongqu1783 2018-12-06 21:20 采纳率: 100%
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一个变量中的两个变量变量

I have a for-loop ($x++) within another for-loop ($i++) , and I want both $x AND $i to be part of a variable variable:

${'name'.$x.'place'.$i.''} = ...;

Such that I get:

  • $name1place1
  • $name1place2
  • $name1place3
  • $name2place1
  • $name2place2
  • $name3place1 etc. etc.

However, setting variables in the way quoted above does NOT work for me (i.e. with single quotations and two variable variables). I get the error "Notice: Undefined variable [...]".

The following works:

${"name$x"} = ...;

(using double quotations and just one variable variable.)

How can I set variable variables with both $x and $i within the variable name? Thank you!

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1条回答 默认 最新

  • doutangxi2144 2018-12-07 04:27
    关注

    You can do this by using curly braces within your variable name assignment to separate $x from the place:

    $x = 4;
    $i = 5;
    ${"name{$x}place{$i}"} = "test";
    echo $name4place5;
    

    Output:

    test
    

    However it would really make a lot more sense to just use an array:

    $name[$x][$i] = "test2";
    echo $name[$x][$i];
    

    Demo on 3v4l.org

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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