doushang1890 2013-02-19 17:43
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php在延迟一段时间后显示下一个值

So I have an array

$super = array(8,9,10,11,12,20,21); 

I want to display first value for one hour in my website

after one hour display second one and etc.

after array reaches the end "21" it resets and starts to display first value

echo $super [0]

wait for one hour $super change to

$super[1]
next hour
 $super[2] 
and etc.

after

$super == $super[21] 
reset
 $super to  $super[0] 

I could use next(), current(), reset() functions, but I can't figure out how to loop them with delay.

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  • douxuan0698 2013-02-19 18:19
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    Enjoy server-side static version:

    $super = array(8,9,10,11,12,20,21); // Array can be extended
    $h = date('H') ; //Current hour. Server time
    
    $start_day_element = 0 ; //Offset, from what element days start.
    
    echo $super[($h + $start_day_element)%count($super)] ;
    

    But of course, page must be refreshed to see updated value.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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