I'm trying to use this code to be able to stop double bookings in my booking system. At the moment when you enter the same time twice then it comes up with this error:
Email is validthis time is already booked
Notice: Undefined variable: sql in C:\xampp\htdocs\book.php on line 44
Warning: mysqli_query(): Empty query in C:\xampp\htdocs\book.php on line 44
Error:
this is my code
<?php
//$error = ""; // Initialize error as blank
$con=mysqli_connect("localhost","","","");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
if ($_SERVER["REQUEST_METHOD"] == "POST")
{
$email = $_POST['email'];
$time = $_POST["time"];
$name = $_POST["name"];
$surname = $_POST["surname"];
$date = $_POST["date"];
$adl1 = $_POST["adl1"];
$adl2 = $_POST["adl2"];
$postcode = $_POST["postcode"];
if(!filter_var(($email), FILTER_VALIDATE_EMAIL))
{
echo "E-mail is not valid";
}
else
{
echo "Email is valid";
$result = mysqli_query($con, "SELECT time FROM tbl_booking WHERE time = '$time'") or trigger_error("Query Failed! SQL: $result - Error: ".mysqli_error($con), E_USER_ERROR);
if(mysqli_num_rows($result) == 0)
{
$sql="INSERT INTO tbl_booking (name, surname, email, date, time, adl1, adl2, postcode) VALUES ('$name','$surname','$email','$date','$time','$adl1','$adl2','$postcode')";
}
else
{
echo("this time is already booked");
}
if (!mysqli_query($con, $sql))
{
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
}
}
Basically I think it's trying to access the $sql
inside the if
statement but I have no idea why it can't. Unless i'm being stupid.