doudi8298 2013-07-20 15:34
浏览 32
已采纳

mysql group by select with condition value

In my messages table I have following rows for example,

|----|---------|--------------|------|
| id | user_id | message      |status|
|====|=========|==============|======|
| 1  |  2      | msgs 11      |  r   |
|----|---------|--------------|------|
| 2  |  3      | msgs 12      |  r   |
|----|---------|--------------|------|
| 3  |  2      | msgs 13      |  r   |
|----|---------|--------------|------|
| 4  |  3      | msgs 14      |  u   |
|----|---------|--------------|------|

Now, I need to know two things for each user_id

  • Whether it has any status u or not.
  • How many messages are there

For example, a query like below select user_id, status, count(*) as totalMsg from messages group by user_id Would brought me following rows

| user_id | status| totalMsg |
|=========|=======|==========|
|  2      |   r   |    2     |
|---------|-------|----------|
|  3      |   r   |    2     | 
              ^
              |------> I need this value to be 'u' because user 3 has a message u

My current query doesnt really gurantee that it will look for a u in the status column. Is that possible to do? If so how?

  • 写回答

1条回答 默认 最新

  • doucan1996 2013-07-20 15:36
    关注

    MAX() will work on this since r is the least value based on the lexicographical order.

    SELECT  user_ID,
            MAX(status) status,
            COUNT(*) totalMsg
    FROM    messages
    GROUP   BY user_ID
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 如何在node.js中或者java中给wav格式的音频编码成sil格式呢
  • ¥15 不小心不正规的开发公司导致不给我们y码,
  • ¥15 我的代码无法在vc++中运行呀,错误很多
  • ¥50 求一个win系统下运行的可自动抓取arm64架构deb安装包和其依赖包的软件。
  • ¥60 fail to initialize keyboard hotkeys through kernel.0000000000
  • ¥30 ppOCRLabel导出识别结果失败
  • ¥15 Centos7 / PETGEM
  • ¥15 csmar数据进行spss描述性统计分析
  • ¥15 各位请问平行检验趋势图这样要怎么调整?说标准差差异太大了
  • ¥15 delphi webbrowser组件网页下拉菜单自动选择问题