dongwolu5275 2018-10-08 16:36
浏览 39
已采纳

无法从php和sqlite db获取表中的数据

I want to echo onto my screen all the data is my 'userdata' table. i have looked around and found this code but when i run it i get a HTTP ERROR 500. this is my code that im trying to use:

<?php
    $database = new SQLite3('home.db');

    $result = $database->query("SELECT * FROM userdata");
    echo $result;
?>
  • 写回答

1条回答 默认 最新

  • dongteng2534 2018-10-08 16:52
    关注

    the $database->query() method will return an SQLite3Result object which you can't just "echo". Instead, you should loop through all the results like so:

    <?php
        $database = new SQLite3('home.db');
    
        $result = $database->query("SELECT * FROM userdata");
    
        while ($row = $result->fetchArray()) {
            print_r($row);
        }
    ?>
    

    The $row variable inside the while loop will be an array. Use the appropriate index to get the value of a single column if necessary.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 如何在scanpy上做差异基因和通路富集?
  • ¥20 关于#硬件工程#的问题,请各位专家解答!
  • ¥15 关于#matlab#的问题:期望的系统闭环传递函数为G(s)=wn^2/s^2+2¢wn+wn^2阻尼系数¢=0.707,使系统具有较小的超调量
  • ¥15 FLUENT如何实现在堆积颗粒的上表面加载高斯热源
  • ¥30 截图中的mathematics程序转换成matlab
  • ¥15 动力学代码报错,维度不匹配
  • ¥15 Power query添加列问题
  • ¥50 Kubernetes&Fission&Eleasticsearch
  • ¥15 報錯:Person is not mapped,如何解決?
  • ¥15 c++头文件不能识别CDialog