使fetch数组包含变量的麻烦

Question

i am trying to loop a database routine, but i have problems making an fetch array contain a variable.g

${"db" . $currentTime . "11"} = ${"data" . $currentTime . "1"}[${$currentTLower . "11"}];

$currentTime contains 'A'

$currentTLower contains 'a'

So line of code would look like this:

$dbA11 = $dataA1[a11];

But, it doesn't do the trick.

Answer 1

You were very close. Index should be 'a11' but not $a11 as in your code

$currentTime = 'A';
$currentTLower ='a';
$dataA1['a11'] = 'value';

${"db" . $currentTime . "11"} = ${"data" . $currentTime . "1"}[$currentTLower . "11"];

echo $dbA11; // value