dounao1875
dounao1875
2019-01-07 04:03

通过匹配相同的外键来组合2个数组

已采纳

I have 2 table, that is a question_table and answer_table the structure is like this : enter image description here

And I have a JSON array that I got from question_table and answer_table using php like this.

// to get the question
$pertanyaan = "select * from question_table”;
$resultPertanyaan = mysqli_query($con, $pertanyaan);

while($rowQuery= mysqli_fetch_array($resultPertanyaan)){
   $array_question[]= 
array('id'=>$rowQuery['id’],’question’=>$rowQuery['question']);
}

and the result is like this

array_question :
[
    {
        "id": "8",
        “question”: "Shop sign/billboard  "
    },
    {
        "id": "10",
        "question": "Pylon"
    },
    {
        "id": “11”,
        “question”: "Banner”
    },
    {
        "id": "12”,
        "question": “Sport”
    },
   {
        "id": “14”,
        “question”: “Matic "
    },
    {
        "id": "16”,
        "question": “Cub”
    }
]

To get the answer

$jawaban = "select * from answer_table”;
$resultJawaban = mysqli_query($con, $jawaban);

while($rowQuery= mysqli_fetch_array($resultJawaban)){
    $array_answer[]=
array('id'=>$rowQuery['id'],'remark'=>$rowQuery['remark'],'item'=>$rowQuery['item']);
}

and the result like this

array_answer :
[
    {
        "id": "1b9fa84e-0f2f-11e9-b673-005056be36b2",
        “answer”: "3",
        “id_question”: "16"
    },
    {
        "id": "bc82c3fd-0f2e-11e9-b673-005056be36b2",
        "answer": "1",
        "id_question": "11"
    },
    {
        "id": "cc9363f1-0f2e-11e9-b673-005056be36b2",
        "answer": "3",
        "id_question": "12"
    },
    {
        "id": "f1dfa8b5-0f2e-11e9-b673-005056be36b2",
        "answer": "1",
        "id_question": "14"
    }
]

I want to combine array_answer with array_question, which results like this:

array_result :
[
    {
        "id": "8",
        “question”: "Shop sign/billboard  ",
        “asnwer” : null
    },
    {
        "id": "10",
        "question": "Pylon”,
        “asnwer” : null
    },
    {
        "id": “11”,
        “question”: "Banner”,
        “asnwer” : “1”
    },
    {
        "id": "12”,
        "question": “Sport”,
        “answer” : “3”
    },
    {
        "id": “14”,
        “question”: “Matic “,
        “answer” : “1”
    },
    {
        "id": "16”,
        "question": “Cub”,
        “answer” : “3”
    }
]

How do I get array_result like I expected? Please help me, Thank you

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2条回答

  • doufei2662 doufei2662 2年前

    You can use array_map to process each of the questions, looking for an answer in $array_answer for each one:

    $questions = json_decode($array_question);
    $answers = json_decode($array_answer, true);
    
    $array_result = array_map(function ($v) use ($answers) {
        $v->answer = ($k = array_search($v->id, array_column($answers, 'id_question'))) !== false ? $answers[$k]['answer'] : null;
        return $v;
    }, $questions);
    print_r(json_encode($array_result, JSON_UNESCAPED_SLASHES));
    

    Output:

    [{"id":"8","question":"Shop sign/billboard ","answer":null},
     {"id":"10","question":"Pylon","answer":null},
     {"id":"11","question":"Banner","answer":"1"},
     {"id":"12","question":"Sport","answer":"3"},
     {"id":"14","question":"Matic ","answer":"1"},
     {"id":"16","question":"Cub","answer":"3"}
    ]
    

    Demo on 3v4l.org

    Update

    For versions of PHP prior to 5.4, there are a couple of issues with the above code. Firstly array_column was not implemented in PHP until version 5.5.0. Secondly the JSON_UNESCAPED_SLASHES constant and associated functionality wasn't implemented until PHP 5.4.0. We can emulate those with this code:

    function my_array_column($array, $column) {
        return array_map(function ($v) use ($column) { return $v[$column]; }, $array);
    }
    
    $array_result = array_map(function ($v) use ($answers) {
        $v->answer = ($k = array_search($v->id, my_array_column($answers, 'id_question'))) !== false ? $answers[$k]['answer'] : null;
        return $v;
    }, $questions);
    echo str_replace('\/', '/', json_encode($array_result));
    

    Demo on 3v4l.org

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  • dongma6326 dongma6326 2年前

    Can you try following code:

    $sql = "select q.id, q.question, a.aswer from question_table q inner join answer_table a ON q.id = a.id_question”;
    $resultPertanyaan = mysqli_query($con, $sql);
    
    while($rowQuery= mysqli_fetch_array($resultPertanyaan)){
       $array_result[]= 
    array('id'=>$rowQuery['id’],’question’=>$rowQuery['question'], 'answer' => $rowQuery['aswer']);
    }
    
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