如何在函数中使用外部变量？ [重复]

Question

This question already has an answer here:

• Reference: What is variable scope, which variables are accessible from where and what are “undefined variable” errors? 3 answers

I saw some other user here asking this and I tried what they said in the answer section, but nothing had worked for me.

I have this variable:

$inputs = \Request::all();
$domain = $inputs['domain'];

Now in $domain is the domain-name I need.

This is my function:

function searchfor ($search)
{
    $path = '/var/www/laravel/logs/vhosts/';
    $shell_exec = shell_exec("grep -c -i $search  $path" . $domain . ".log");
    return $shell_exec;
}

This haven't worked cause of course PHP doesn't know what $domain is.

Now I tried put a global $domain; in the function but this haven't worked either.

I also tried this:

function anzahlsuche($search) use ($domain) { ... }

But it's the same, it doesn't worked for me.

Does somebody have another idea what I can do?

I'm using the Laravel Framework, maybe someone knows a solution in laravel, normal php would do it too, of course.

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Answer 1

two options - pass the variable as a parameter to the function or use the global expression to name the variable within the function. The variable must be available in the scope that the function is called.

 $inputs = \Request::all();
 $domain = $inputs['domain'];

 function anzahlsuche($search,$domain)
        {
            $path = '/var/www/laravel/logs/vhosts/';
            $shell_exec = shell_exec("grep -c -i $search  $path" . $domain . ".log");
            return $shell_exec;
        }

 function anzahlsuche($search)
        {
            global $domain;
            $path = '/var/www/laravel/logs/vhosts/';
            $shell_exec = shell_exec("grep -c -i $search  $path" . $domain . ".log");
            return $shell_exec;
        }