如何将include绑定到php [duplicate]中的关联数组

Question

This question already has an answer here:

• require/include into variable 9 answers

I have 2 echo's from a php script that are sent as json to the ajax call. These 2 echos will be outputted in 2 different divs. For those 2 echo's , I created an array like below:

 $result = [
    "one" => "this is echo 1",
    "two" => "this is echo 2"
];
echo json_encode($result);

Instead of these echo's, I now want to include 2 files (which will be the echos). Sow can I do that?

So what I want is something like this:

$result = [
    "one" => include('success.php'),
    "two" => include('renderfiles.php')
];

How can I do this?

By the way, this is my jquery ajax:

$.ajax({
url: "",
type: "post",
data:  new FormData(this),
dataType: 'json',
contentType: 'application/json',
    success: function(data) {
       $('.echo').html(data.one); // content ofinclude success.php should come here
   $('.table-content').html(data.two); // content of include renderfiles.php should come here

</div>

Answer 1

In your include files, you will need to return the HTML - or use output buffering to capture it and then return the contents. Using return ...

$result = [
    "one" => include('success.php'),
    "two" => include('renderfiles.php')
];

So the contents of success.php would be something like

return "<sometag></sometag>";

This makes sure that the value is passed back and inserted in the correct place and will give something like

{"one":"<sometag><\/sometag>","two":...}

If you just echo the HTML,

echo "<sometag></sometag>";

you may end up with something like

<sometag></sometag>{"one":1,"two":"a"}