PHP - “通知：未定义的变量：行” - 无法获取MySQL的记录[重复]

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• “Notice: Undefined variable”, “Notice: Undefined index”, and “Notice: Undefined offset” using PHP 28 answers

this is my first programming question on the internet.

I already made some research, tried to change something, but so far, nothing solved my problem.

I have the code below:

$sql = "SELECT * FROM tb_carros_of";
$result = mysqli_query($con, $sql) or die("Error: ".mysqli_error($con));
while($row = mysqli_fetch_array($result))
{
  echo strtoupper($row['no_escud']);
}

The problem is: the exact code works fine on an external website, but locally, on my computer, it returns the error "Notice: Undefined variable: row" on the line starting with "echo ...";

What am I missing?

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Answer 1

guys! I just found how to solve the problem! Sorry I didn't provide you the wholle code at first. I would do it next time. The problem is that I didn't provide the closing mark ?> at the end of my file. I just did it, and the db records showed up in the browser! Although I don't know how the external website is working without the closing mark.