PHP preg_match_all在选项值中没有禁用选项

Question

Any suggestion how to do the result value option without disabled option with php preg_match_all?

<option value="1" disabled="disabled"> google</option>
<option value="2" selected="selected">- yahoo</option>
<option value="3">- youtube</option>
<option value="4">- facebook</option>
<option value="5" disabled="disabled"> twitter</option>
<option value="6">- tumblr</option>
<option value="7">- bing</option>

how to echo just value without disabled options maybe with preg_match_all?

i have some code but not work,

   $string = array(
   '/<option value=\"(.*)\" selected=\"selected\">-/sU',
   '/<option value=\"(.*)\">-/U',);

$option = curl_exec($ch);
foreach ($string as $key) {
 if (preg_match_all($key, $option, $matches)) {
  $count = count($matches[1]);
    for ($i=0; $i < $count ; $i++) { 
     echo $matches[1][$i]."
";
  }
 }else {
   echo "match NOT found";
 }
}

i want to the result like this,

value = 2,3,4,6,7

thanks for helping,

Answer 1

Using XPath is easy, check the following solution:

$doc = new DOMDocument();
$doc->loadHTML('<option value="1" disabled="disabled"> google</option><option value="2" selected="selected">- yahoo</option><option value="3">- youtube</option><option value="4">- facebook</option><option value="5" disabled="disabled"> twitter</option><option value="6">- tumblr</option><option value="7">- bing</option>');

$xpath = new DOMXPath($doc);
$notDisabledOptions = $xpath->query("//option[not(@disabled)]");
$numberOfOptions = $notDisabledOptions->length;

for($i = 0; $i < $numberOfOptions; $i++){
      echo $notDisabledOptions->item($i)->attributes->getNamedItem("value")->nodeValue;
}

For more info on how to use XPath, check this XPath tutorial.