加快对同一个mysql服务器，不同表的请求

Question

I have a pretty simple mysql request, 1. request calls to table to get an id, if an id exists function ends, if no id, then the id is not banned and 2nd requests, see if the id exists in public table, if no it adds, if it does it counts up 1 for a page view.

Currently this function seems to be causing a serious slow down. af_ban table has about 8000 rows af_freefeed table has about 1,000,000 rows. About 10,000 rows added per day.

function pageview($pageid, $pagename){
$sql=mysql_num_rows(mysql_query("SELECT * FROM anotherfeedv3.af_ban WHERE pageid = '".$pageid."'"));
    if(!$sql){
        $sql=mysql_num_rows(mysql_query("SELECT pageid FROM anotherfeedv3.af_freefeed WHERE pageid = '".$pageid."'"));
            if(!$sql){
            $sql = 'INSERT INTO `anotherfeedv3`.`af_freefeed` (`id`, `pageid`, `userid`, `views`, `pagename`) VALUES (NULL, \''.$pageid.'\', \'\', \'1\', \''.htmlspecialchars($pagename, ENT_QUOTES).'\');';
            $insert=mysql_query($sql) or die ('Error! in Insert '.$pageid.' SQL');
            }else{
            $sql = 'UPDATE `anotherfeedv3`.`af_freefeed` SET `pagename` = \''.htmlspecialchars($pagename, ENT_QUOTES).'\', views=views+1 WHERE `af_freefeed`.`pageid` = '.$pageid.';';
            //$sql = 'UPDATE `anotherfeedv3`.`af_freefeed` SET views=views+1 WHERE `af_freefeed`.`pageid` = '.$pageid.';';
            $update=mysql_query($sql) or die ('Failed update of '.$pageid.' in mysql.');
        }
    }
};

Is there a better way i can write this?

---

Solution!

function pageview($pageid, $pagename){
$q = sprintf('SELECT COUNT(*) AS numrows FROM anotherfeedv3.af_ban WHERE pageid = %d', $pageid);
$r = mysql_query($q);
$a = mysql_fetch_assoc($r);
if($a['numrows'] > 0){ /* ... */ }else {
    $q = sprintf('SELECT COUNT(*) AS numrows FROM anotherfeedv3.af_freefeed WHERE pageid = %d', $pageid);
    $r = mysql_query($q);
    $a = mysql_fetch_assoc($r);
    if($a['numrows'] > 0){ /* ... */ 
    $sql = 'UPDATE `anotherfeedv3`.`af_freefeed` SET `pagename` = \''.htmlspecialchars($pagename, ENT_QUOTES).'\', views=views+1 WHERE `af_freefeed`.`pageid` = '.$pageid.';';
            //$sql = 'UPDATE `anotherfeedv3`.`af_freefeed` SET views=views+1 WHERE `af_freefeed`.`pageid` = '.$pageid.';';
    $update=mysql_query($sql) or die ('Failed update of '.$pageid.' in mysql.');
    }else {
    $sql = 'INSERT INTO `anotherfeedv3`.`af_freefeed` (`id`, `pageid`, `userid`, `views`, `pagename`) VALUES (NULL, \''.$pageid.'\', \'\', \'1\', \''.htmlspecialchars($pagename, ENT_QUOTES).'\');';
            $insert=mysql_query($sql) or die ('Error! in Insert '.$pageid.' SQL');
    }
}

Answer 1

With these rows:

$sql=mysql_num_rows(mysql_query("SELECT * FROM anotherfeedv3.af_ban WHERE pageid = '".$pageid."'"));
if(!$sql){ /* ... */ }

It appears that you're only interested in whether results exist.

If thats the case, you could replace it with something like:

$q = sprintf('SELECT COUNT(*) AS numrows FROM anotherfeedv3.af_ban WHERE pageid = %d', $pageid);
$r = mysql_query($q);
$a = mysql_fetch_assoc();
if($a['numrows'] > 0){ /* ... */ }

You could condense this, but I split it up pretty liberally for ease of understanding.

Basically, this lets MySQL determine the number of rows without generating a results set.

Further, you could use this technique to combine the first two queries:

$q = 'SELECT (';
$q.= '    SELECT COUNT(*) FROM anotherfeedv3.af_ban WHERE pageid = %d';
$q.= ') AS banrows, (';
$q.= '    SELECT COUNT(*) FROM anotherfeedv3.af_freefeed WHERE pageid = %d';
$q.= ') AS freerows';
$r = mysql_query(sprintf($q, $pageid, $pageid);
$a = mysql_fetch_assoc();

The result of the query will be one row with two columns (banrows, freerows). The values will be the number of rows that match the respective queries above.

You would then use $a['banrows'] and $a['freerows'] to get the row counts for your later logic.

If you're running this query multiple times, there may be some additional performance improvement to be seen if you use PDO and PDO::prepare().