获取通过cURL POST发送的文件的内容

Question

So after researching a bit, I found out that it is possible to send a file through cURL to another page. Here is the code that is doing the sending part:

$url = 'http://someabc.com/api.php';
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_VERBOSE, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, true);
$postData = array(
    'array' => "@".realpath('array.txt'),
);
curl_setopt($ch, CURLOPT_POSTFIELDS, $postData);
$response = curl_exec($ch);

echo $response;

Receiving Part (api.php)

if(isset($_POST['array']))
{
    $string = $_POST['array'];
    echo $string;
}
else
{
    echo 'Not found';
}

When I run the page containing the cURL request, I'm getting Not found printed on the page.

Does this mean I'm capturing the data in a wrong way? If so, what would be the way to get the contents of array.txt from api.php page?

UPDATE

After using $_FILES as suggested by Jon, I received the following array:

Array
(
    [name] => array.txt
    [type] => application/octet-stream
    [tmp_name] => /tmp/phpPQZXf9
    [error] => 0
    [size] => 77413
)

Now I tried getting the contents of this file using:

$tmp = $_FILES['array'];
$string = file_get_contents($tmp['name']['tmp_name']);

but got the error Warning: file_get_contents(a) [function.file-get-contents]: failed to open stream: No such file or directory which would mean I'm not referencing the file correctly. Where did I go wrong now?

Answer 1

For the first part before the update, the problem exists because when posting a file to a page, regardless of the method in which it happens (ie <input type='file />, curl, etc) it is always available to PHP via the $_FILES variable, which is an associative array, in your case, should be $_FILES['array'] containing the information of the temporary file location. The array should be similar to:

Array 
(
    [array] => Array
    (
            [name] => array.txt
            [type] => encoding type
            [tmp_name] => /tmp/path/file
            [error] => 0 (if no error)
            [size] => [filesize]
    )
)

From there, to access the file, you'd want to move it from the tmp directory to one you have permission to access. This is accomplished with move_uploaded_file. An example of usage with this would be:

$upDir = 'uploads/';
move_uploaded_file($_FILES['array']['tmp_name'], $upDir. $_FILES['array']['name']);

From there, the file will be on the server under the relative path to the php file in uploads/array.txt, and you can do what you will with it there. ^^