dongxiao3694 2016-03-02 10:48
浏览 113

想要接收使用php通过ajax发送的json数据并将其存储在db中

following is my js

            var obj = {};
            obj["name"] = uname;
            obj["repo"] = repo;
            obj["length"] = linelength;
            var json = JSON.stringify(obj);
            $.ajax({
                method: "POST",
                url: "example.php",
                data: {'data' : json},
                success: function(response){
                    console.log("success");
                }
            });

and following is my php

<?php
include("connection.php");
if(isset($_POST["data"])){
    $myData = $_POST["data"];
    $ddata = json_decode($myData);
    $name = $ddata->name;
    $repo = $ddata->repo;
    $length = $ddata->length;
    $query = "INSERT INTO user('name', 'repo', 'length') VALUES($name, $repo, $length)";
    $db->exec($query);
}   ?>

The log is showing success but the data are not getting added in db. Your help will be appreciated

  • 写回答

3条回答 默认 最新

  • doucang2871 2016-03-02 10:50
    关注

    Column names should be enclosed (if at all) with backticks ` and values enclosed in single quotes ':

    $query = "INSERT INTO user (`name`, `repo`, `length`)
              VALUES ('$name', '$repo', '$length')";
    

    However, I would say that your code is vulnerable to injection and you should use placeholders - switch to using prepared statements!

    评论

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