如何使用php命令行在一行中获取多个标准输入

Question

like Input is:
3
1 2
2 3
4 5

I have to take those input in given style. Here (1 and 2), (2 and 3) and (4 and 5) have to take in one line as a input.

Here is my code snippet.

 <?php
header('Content-Type: text/plain');

$testCase = (int) fgets(STDIN);

while($testCase--) {
    $myPosition = (int) fgets(STDIN);
    $liftPosition = (int) fgets(STDIN);
}

Implementation in C++

int main()
{
   int testcase, myPos, liftPos;

   cin >> testcase;

   while(testcase--)
   {
      cin >> myPos >> liftPos;
   }
}

So, how can implement the C++ code in PHP ?

Answer 1

Actually, the problem is in the following line:

$myPosition = (int) fgets(STDIN);

Here, the explicit conversion to int is discarding the value after space, so when you give 1 2 as the input in the command line the (int) is turning it into 1 and you are losing the other character.

$arr = [];
$testCase = (int) fgets(STDIN);

while ($testCase--) {
    list($a, $b) = explode(' ', fgets(STDIN));
    $arr[] = $a.' '.$b;
}

print_r($arr);

The above solution works because I've removed the (int) from the beginning of the fgets. Also note that, I'm using list($a, $b) here, which will actually create two variable $a and $b in the current scope so I'm always assuming that, you'll use two separate numbers (i.e: 1 2), otherwise you can use $inputParts = preg_split("/[\s]+/",$input) or something else with explode to form the array from input from console.