包含在不使用array-PHP的情况下连接的单词的回显字符串

Question

I have a string which comprises of the words the user input in it so I don't know how many words will be there and what will be the index of each word so that I can find substring out of this. Can anyone tell me how to echo it without using or converting it into array and add next line whenever there is space in string. I am newbie to php. I checked for split method, explode method, all inbuilt methods are converting it into array which i dont need.

$var= "This is a sample code."

I want output like this:

This
is 
a
sample 
code

I tried this but it didnt work for me.

$count= str_word_count($var);
        echo "$count";
        $strlen= strlen($var);
        for($i=0; $i<(int)$strlen;$i++ ){
          if($var contains " "){
          echo "
";
        }else {
          echo $var;
        }
        }

I would appreciate your help. Thank you.

Answer 1

Without other builtin functions and just using for loop , This will give the expected output

 for($i=0; $i<(int)$strlen;$i++ ){
          if($var[$i]==" "){
          echo "<br>";
        }else if($var[$i] !='.'){
          echo $var[$i];
        }
  }