找到字符串中大于特定数字的任何数字的第一个出现位置

Question

I have this string: "20 plus 1000 is not 20000."

And I want to get the position of the first number bigger than 10000.

I'm actualy (and for a different purpose) using this first answer code to get the position of the first number in my string:

function firstNumPos($text){
  preg_match('/^\D*(?=\d)/', $text, $m);
  return isset($m[0]) ? strlen($m[0]) : false;
}

But it doesn't distinguish between number sizes, so, what could be missing for this function to get the position of the first occurence of a number bigger than 10000?

Any solution is welcome, not necessarily by using that function.

Answer 1

function firstNumPos($text, $number){
  preg_match_all('!\d+!', $text, $match);
  foreach ($match[0] as $value) {
      if ($value > $number) {
          return strpos($text, $value);
      }
  }
}

echo firstNumPos('20 plus 1000 is not 20000.', 10000);