donglan8999 2016-02-26 07:05
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将两个非常相似的PHP函数合并为一个

I have two almost identical functions and I am not familiar with PHP but need just a bit of work around. I have several functions as the two shown here and I would like to know how can I merge both of them into one. I use PHP-5.4

function is_checked_gen($block_name, &$curr_rec, $rec_num) {
     global $gen_checked;
     global $gen_list;

     if (in_array($curr_rec[val], $gen_checked)) {
              $curr_rec['checked'] = 'checked';
              $gen_list .= " " . $curr_rec[val];
     } else {
              $curr_rec['checked'] = '';
     }
}

function is_checked_veh($block_name, &$curr_rec, $rec_num) {
     global $veh_checked;
     global $veh_list;

     if (in_array($curr_rec[val], $veh_checked)) {
              $curr_rec['checked'] = 'checked';
              $veh_list .= " " . $curr_rec[val];
     } else {
              $curr_rec['checked'] = '';
     }
}
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4条回答 默认 最新

  • doubu1950 2016-02-26 07:17
    关注

    In each function, only the corresponding list is getting updated when checked is found in the array. hence pass that list as reference and update it.

    function is_checked($block_name, &$curr_rec, $rec_num, $checked, &$list) {
    
         if (in_array($curr_rec[val], $checked)) {
                  $curr_rec['checked'] = 'checked';
                  $list .= " " . $curr_rec[val];
         } else {
                  $curr_rec['checked'] = '';
         }
    }
    
    is_checked($block_name, $curr_rec, $rec_num, $gen_checked, $gen_list);
    is_checked($block_name, $curr_rec, $rec_num, $veh_checked, $veh_list);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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