Mysql PHP，如何选择以特定字符开头的数据

Question

I have a table cities:

+----+--------+
| id | zip    | 
+----+--------+
|  1 | 07500  | 
|  2 | 07501  | 
|  3 | 75000  | 
|  4 | 75001  | 
|  5 | 75002  | 
+----+--------+

And I need to select data where the field zip start with 750, so I've tried :

SELECT FROM cities WHERE ZIP LIKE '%750%'

But this returns me all data in the table that contain 750 and this isn't normal. How could I tell my query to select data that start with 750 ?

Answer 1

Do this query:

SELECT FROM cities WHERE ZIP LIKE '750%'

Explanation

% is a special MySQL character that means any character, empty string or group of characters.

Examples:

LIKE '%a%' -- matches: a, ant, track | any string that contains a in any location
LIKE 'a%'  -- matches: a, ant        | strings that start with a
LIKE '%a'  -- matches: a, data       | strings that end with a