duanfan5012 2019-07-22 08:32
浏览 78
已采纳

没有得到预期的PHP cURL响应

I have the following PHP code:

<?php
$data = array("client_id" => "sipgate-app-web", "grant_type" => "password", "username" => "my_username", "password" => "my_password");
$data_string = json_encode($data);

$ch = curl_init('https://api.sipgate.com/login/sipgate-apps/protocol/openid-connect/token');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/x-www-form-urlencoded',
'Accept: application/json'
));

$result = curl_exec($ch);

echo $result;
?>

Unfortunately, I'm not getting the expected response. The response I'm receiving is:

{"error":"invalid_request","error_description":"Missing form parameter: grant_type"}

When using an online cURL tool like https://onlinecurl.com with the same data (URL, header, data) as in my cURL PHP code, I'm getting the right response. This means, there's something wrong with my PHP code. I'm not getting any error in the PHP error log.

The manual says I have to use the following cURL code:

 curl \
--request POST \
--header 'Content-Type: application/x-www-form-urlencoded' \
--header 'Accept: application/json' \
--data-urlencode "client_id=sipgate-app-web" \
--data-urlencode "grant_type=password" \
--data-urlencode "username=my_username" \
--data-urlencode "password=my_password" \
https://api.sipgate.com/login/sipgate-apps/protocol/openid-connect/token

Since I'm new to cURL, after googling a lot, I have no idea what I'm doing wrong.

Can anybody help me?

EDIT: You can test my PHP code above as it is. You should get the following response, if the code is working:

{"error":"invalid_grant","error_description":"Invalid user credentials"}

  • 写回答

2条回答 默认 最新

  • dongya1228 2019-07-22 08:49
    关注

    As per the manual, your request needs to have the Content-Type of application/x-www-form-urlencoded which looks like this:

    key1=value1&key2=value2
    

    Thus you need to convert your array into such a string either manually or with http_build_query, like so:

    $data_string = http_build_query( $data );
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 流式socket文件传输答疑
  • ¥20 keepalive配置业务服务双机单活的方法。业务服务一定是要双机单活的方式
  • ¥50 关于多次提交POST数据后,无法获取到POST数据参数的问题
  • ¥15 win10,这种情况怎么办
  • ¥15 如何在配置使用Prettier的VSCode中通过Better Align插件来对齐等式?(相关搜索:格式化)
  • ¥100 在连接内网VPN时,如何同时保持互联网连接
  • ¥15 MATLAB中使用parfor,矩阵Removal的有效索引在parfor循环中受限制
  • ¥20 Win 10 LTSC 1809版本如何无损提升到20H1版本
  • ¥50 win10 LTSC 虚拟键盘不弹出
  • ¥15 寻找能匹配的液晶显示屏。