duanfan5012 2019-07-22 08:32
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没有得到预期的PHP cURL响应

I have the following PHP code:

$data = array("client_id" => "sipgate-app-web", "grant_type" => "password", "username" => "my_username", "password" => "my_password");
$data_string = json_encode($data);

$ch = curl_init('https://api.sipgate.com/login/sipgate-apps/protocol/openid-connect/token');
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, $data_string);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, array(
'Content-Type: application/x-www-form-urlencoded',
'Accept: application/json'

$result = curl_exec($ch);

echo $result;

Unfortunately, I'm not getting the expected response. The response I'm receiving is:

{"error":"invalid_request","error_description":"Missing form parameter: grant_type"}

When using an online cURL tool like https://onlinecurl.com with the same data (URL, header, data) as in my cURL PHP code, I'm getting the right response. This means, there's something wrong with my PHP code. I'm not getting any error in the PHP error log.

The manual says I have to use the following cURL code:

 curl \
--request POST \
--header 'Content-Type: application/x-www-form-urlencoded' \
--header 'Accept: application/json' \
--data-urlencode "client_id=sipgate-app-web" \
--data-urlencode "grant_type=password" \
--data-urlencode "username=my_username" \
--data-urlencode "password=my_password" \

Since I'm new to cURL, after googling a lot, I have no idea what I'm doing wrong.

Can anybody help me?

EDIT: You can test my PHP code above as it is. You should get the following response, if the code is working:

{"error":"invalid_grant","error_description":"Invalid user credentials"}

  • 写回答

2条回答 默认 最新

  • dongya1228 2019-07-22 08:49

    As per the manual, your request needs to have the Content-Type of application/x-www-form-urlencoded which looks like this:


    Thus you need to convert your array into such a string either manually or with http_build_query, like so:

    $data_string = http_build_query( $data );
    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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