如何使用PHP删除JSON中的方形括号

Question

Below code is the returned JSON

[{"one":"id","two":"id","three":"id"},{"one":"id","two":"id","three":"id"}]

Below code is the desired result of the returned JSON (without the array bracket)

{"one":"id","two":"id","three":"id"},{"one":"id","two":"id","three":"id"}

Below code is to convert the array to the JSON format

include('connect-db.php'); 
$result = mysql_query("SELECT * FROM patientvaccinedetail"); 
$specific = []; 
while($row = mysql_fetch_array( $result ,MYSQL_ASSOC)) { 
echo "<tr>"; 
echo '<td width="100px">' . $row['id'] . '</td>'; 
echo '<td width="200px">' . $row['patientid'] . '</td>'; 
echo '<td width="200px">' . $row['vaccineid'] . '</td>'; 
  //**********Convert the array into json******************* 

  $specific[] = ["one" => $row["id"],
                 "two" => $row["patientid"],
                 "three" => $row["vaccineid"]];

$result = json_encode($specific,JSON_UNESCAPED_UNICODE);

echo $result;
echo "</tr>";
echo "</table>";
?>

To send the request to the API, iam using Guzzle And the format the API require is {xx:xx},{xx:xx} without the square bracket, any idea how to remove it using PHP. Thanks in advance

     $client = new Client([
    'headers' => ['Content-Type' => 'application/json',
                  'Token' => $token]
                           ]);

       $response = $client->post('http://localhost:91/Religious',
       ['body' => ***Where the json will be place***]
       );

Answer 1

My suggestion is to use JSON string and perform String operations to remove all those not required characters.

Reason for doing this, the required output is not a valid JSON and won't be accepted by API. As you need it however, I would suggest you to convert the array into json using json_encode and then perform string operations to convert it into your desired output.