如何使用php / smarty确定网站的路径？

Question

Ok, say I have a page with the url: URL.com/checkout/completed, how can I setup an if statement to perform:

<if "This page has url of checkout/completed">

No Content

<else>

Content

</if>

Is there a way? A simple way, my php/smarty-fu lacks.. A lot.

EDIT:

{if $smarty.server.REDIRECT_URL eq 'http://www.euroworker.no/checkout/completed'}
 
{else}  
<div id="scrollwrap">   
    <div class="scrollFieldContent"> 

Scrolled content
        </div>

<div class="probetalings">Velg betalingsmåte</div>

{include file="/choosePaymentMethod.tpl"}
</div> 

{/if}

Thanks.

Answer 1

Have a look at $_SERVER['REQUEST_URI']; and $_SERVER['REDIRECT_URL'];

if($_SERVER['REDIRECT_URL'] == 'checkout/completed') {
   echo 'Some content';
}

in smarty:

{if $smarty.server.REDIRECT_URL eq 'checkout/completed'}
Some content
{/if}

If you don't have REDIRECT_URL set, and use REQUEST_URI, you might want to use strstr instead of typical comparison in case you just want to match that URI while ignoring any additional parameters which might be sent, or go with SCRIPT_NAME as @Pekka suggested:

if(strstr($_SERVER['REQUEST_URI'], 'checkout/completed')) {
   echo 'Some content';
}

EDIT: Try:

{if $smarty.server.REQUEST_URI eq '/checkout/completed'}