函数变量来自包含文件 - php

Question

I haven't found a very good answer to my problem so I'm starting a new topic. I have the file english.php which has variables like $lang['fname'] = "First name";. Also I have header.php which includes english.php : include('english.php');. Now, header.php is included in another php page, let say addInfo.php. If I write in addInfo.php : echo $lang['fname']; it shows me "First name", but if i write a function in addInfo.php, as example function added () { echo $lang['fname'];} and then added(); (i tried also echo added()) it doesn't want to display the value("First name"). Does somebody know a solution for this sample(i think) problem. I'm ready to try all answers. Regards, StefanZ

Answer 1

When you write this :

function added () {
    echo $lang['fname'];
} 

PHP will search for a $lang variable that is local to the function :

• it will not see the global one that's declared outside of the function.
• and, as there is no $lang variable set, inside the function, $lang['fname'] will be null -- i.e. it will not display anything when echoed.

To indicate to PHP that it should use the global variable from outside the function, you need to declare the variable as global, inside the function :

function added () {
    global $lang;
    echo $lang['fname'];
} 

For more informations, you should read the Variable scope section of the PHP manual.