减少3个多个路由到一个功能？

Question

I've been looking all over online and can't find anything that tells you how to assign multiple routes to one callback. For example I want to move:

$app->get('/sign-in', function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

$app->get('/login', function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

into something like:

$app->get(['/sign-in', '/login'], function($request, $response) {
    return $this->view->render($response, 'home.twig');
});

Is there a way to do this with Slim 3? I found online that in Slim 2 you could use the conditions([]); function on the end to chain multiple routes to one callback.

Answer 1

It seems that you can simply define an array and loop through it to create multiple routes on one funciton.

$routes = [
    '/',
    '/home', 
    '/sign-in',
    '/login',
    '/register',
    '/sign-up',
    '/contact'
];

foreach ($routes as $route) {
    $app->get($route, function($request, $response) {
        return $this->view->render($response, 'home.twig');
    });
}