Ext desktop例子中如何使用后台的数据生成开始菜单？

Question

大家好，我是Ext的新手，遇到一个解决不了的问题，希望有大侠帮助

从后台读进的数据像是这样：

{menuName:'funcitionOne', menuCode:'001', parentCode:'0' }
{menuName:'subFunctionOne', menuCode:'001001, parentCode:'001' }
{menuName:'sub-subFunctionOne', menuCode:'001001001', parentCode:'001001'}
{menuName:'sub-subFunctionTwo', menuCode:'001001002 'parentCode:'001001'}

然后根据functionCode和parentCode生成依赖关系的菜单

然后能生成的菜单就像这样：

[img]/upload/attachment/139393/cdbf5c25-b5f9-3208-9ea2-bb8510a606fe.jpg[/img]

Answer 1

要不你就自己遍历json来生成MenuItem,要不你就用这个扩展:
ext.ux.menu.storemenu
见[url]http://atian25.iteye.com/blog/447342[/url]