给你一个数怎么用这个数读出这个代码的英文？

Question

例如一个自然数n，0< =n< =2^31-1。

输出描述
输出这个数的英文，最后不要有多余的空格。
用例输入 1 
1111111111
用例输出 1 
one billion one hundred and eleven million one hundred and eleven thousand one hundred and eleven

Answer 1

该回答引用ChatGPT
可以使用递归的方法来将给定的自然数转换成英文。具体的转换过程可以根据数值的范围和数位来分类讨论，下面是一种实现方式：

#include <iostream>
#include <string>
using namespace std;

// 将0~19的数字转换成英文
string ones[] = {"", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine",
                 "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
// 将20, 30, 40, ..., 90的数字转换成英文
string tens[] = {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"};
// 将数字的数位转换成英文
string scale[] = {"", "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "septillion", "octillion", "nonillion"};

// 将3位数以内的数字转换成英文
string convert(int num) {
    if (num == 0) {
        return "";
    } else if (num < 20) {
        return ones[num];
    } else if (num < 100) {
        return tens[num / 10] + " " + ones[num % 10];
    } else {
        return ones[num / 100] + " hundred " + convert(num % 100);
    }
}

// 将整数转换成英文
string toEnglish(int num) {
    if (num == 0) {
        return "zero";
    }
    string result = "";
    int i = 0;
    while (num > 0) {
        int threeDigits = num % 1000;
        if (threeDigits > 0) {
            result = convert(threeDigits) + " " + scale[i] + " " + result;
        }
        num /= 1000;
        i++;
    }
    return result;
}

int main() {
    int n;
    cin >> n;
    cout << toEnglish(n) << endl;
    return 0;
}