php - 检查条件中的命名空间

Question

I want my code to display "yes" if the scan function as the namespace "Imperium" as a parameter and displays "no" if it doesn't match Imperium

Here is what I tried:

namespace Imperium;
    class Soldier
    {
        public function getNameSpace()
        {
            return __NAMESPACE__;
        }
    }

namespace Chaos;
    class Soldier
    {
        public function getNameSpace()
        {
            return __NAMESPACE__;
        }
    }

class Scanner
{
    public function scan($Soldier)
    {
        if ($Soldier->getNameSpace() == "Imperium")
        {
            echo "yes
";
        }
        else
        {
            echo "no
";
        }
    }
}

$scan = new Scanner();
$scan -> scan(Imperium);

ERROR I get

PHP Fatal error: Uncaught Error: Call to a member function getNameSpace()

Answer 1

In your code you're checking $Soldier->getNameSpace() but you're not giving it a Soldier instance when you call scan()

namespace Imperium {
    class Soldier
    {
        public function getNameSpace()
        {
            return __NAMESPACE__;
        }
    }
}

namespace Chaos {
    class Soldier
    {
        public function getNameSpace()
        {
            return __NAMESPACE__;
        }
    }
}

namespace {
class Scanner
{
    public function scan($Soldier)
    {
        if ($Soldier->getNameSpace() == "Imperium")
        {
            echo "yes
";
        }
        else
        {
            echo "no
";
        }
    }
}

    $soldier = new Imperium\Soldier();
    $scan = new Scanner();
    $scan->scan($soldier); /* Here giving it a soldier instance from imperium namespace */

}