I have an outer div with max-height of 800px.
Within that I could have one or two divs (depends of results from mysql query), the second of which should always be fixed to the bottom of its parent. I can do this with absolute positioning but how do i resize the first child to take the second absolutely positioned div into account?
If only one div is created then I want it to take up the full height of its parent.
Any ideas on how to do this.
Please help!
分享 I would recommend using jQuery or some other easy to use javascript DOM manipulation library. Setting the proper height is then very easy:
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<style type="text/css">
.container {
height: 400px;
background-color: #99CCFF;
position: relative;
top: 0;
left: 0;
}
.first {
background-color: #FFCCFF;
width: 100%;
}
.second {
position: absolute;
bottom: 0;
left: 0;
width: 100%;
background-color: #CCFFCC;
}
</style>
<script src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-2.0.3.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function () {
var height = $('.container').height() - $('.second').outerHeight();
$('.first')
.height(height);
});
</script>
</head>
<body>
<div class="container">
<div class="first">
<h1>This is first div.</h1>
</div>
<div class="second">
<h1>This is second div.</h1>
<ul>
<li>item1</li>
<li>item2</li>
<li>item3</li>
<li>item4</li>
<li>item5</li>
<li>item6</li>
</ul>
</div>
</div>
</body>
</html>
