获取正则表达式的链接文本

Question

How would one parse the content inside these tags, assuming the link is dynamic?

<h3 class="lvtitle">
<a href="http://www.ebay.com/itm/Chicago-Chicago-XXX-Audio-CD-/351478948979?hash=item51d5c72473" 
 class="vip" title="Click this link to access Chicago, Chicago XXX Audio CD">
Chicago, Chicago XXX Audio CD
</a>
</h3>

What I'm after is getting the "Chicago, Chicago XXX Audio CD" part.

Answer 1

Parser example:

$string = '<h3 class="lvtitle"><a href="http://www.ebay.com/itm/Chicago-Chicago-XXX-Audio-CD-/351478948979?hash=item51d5c72473"  class="vip" title="Click this link to access Chicago, Chicago XXX Audio CD">Chicago, Chicago XXX Audio CD</a></h3>';
$doc = new DOMDocument(); //make a dom object
$doc->loadHTML($string); // load the string into the object
$links = $doc->getElementsByTagName('a'); //get all links
foreach ($links as $link) { //loop through all links
    echo $link->nodeValue; //output text content of links
}

Output:

Chicago, Chicago XXX Audio CD

References:
http://php.net/manual/en/domelement.getelementsbytagname.php
http://php.net/manual/en/domdocument.loadhtml.php

...or if you really required a regex for some reason ( I don't see why parser wouldn't work)...

$string = '<h3 class="lvtitle"><a href="http://www.ebay.com/itm/Chicago-Chicago-XXX-Audio-CD-/351478948979?hash=item51d5c72473"  class="vip" title="Click this link to access Chicago, Chicago XXX Audio CD">Chicago, Chicago XXX Audio CD</a></h3>';
preg_match_all('~<a\h.*?>(.*?)</a>~', $string, $links_content);
print_r($links_content[1]);

Output:

Array
(
    [0] => Chicago, Chicago XXX Audio CD
)

~ = delimiter
<a = literally match <a
\h = a horizontal white space
.*? = anything untile the first occurrence of the next character
> = a literal >
(.*?) = a capture grouping capturing everything until the next character again
</a> = literal </a>
~ = closing delimiter

If you prefer regex101 write up, https://regex101.com/r/sT6yA9/1.

Also note the preg_match_all that was incase your string had multiple links in it. With a single occurrence you could use preg_match.