为什么在Go中将两个time.durations相除会导致另一个time.duration？

Question

I don't understand what it means to divide a time.Duration in Go.

For example, this is super lovely:

d,_ := time.ParseDuration("4s")
fmt.Println(d/4)

print 1s. Which is ace, because (naively) 4 seconds divided by 4 is 1 second.

It gets a little confusing though when we find out that the 4 in the denominator has to be a duration. So although:

d1 := time.Duration(4)
fmt.Println(d/d1)

also prints 1s, we know that d1 is actually 4ns and I'm entirely unconvinced that 4 seconds divided by 4 nanoseconds is 1 second.

I'm confused because a duration divided by duration should be dimensionless (I think, right?), whereas a duration divided by a dimensionless number should have units of time.

And I know that type != unit, but I'm clearly misunderstanding something, or quite possibly a set of things. Any help to clear this up would be most appreciated!

Here is a go playground of the above examples. https://play.golang.org/p/Ny2_ENRlX6. And just for context, I'm trying to calculate the average time between events. I can fall back to using floats for seconds, but am trying to stay in time.Duration land.

Answer 1

It is so because time.Duration is int64. See documentation of time package.

You make a division of 4000000000 (4s) by 4 (4ns) and you get 1000000000 (1s). You should look at the operations as they where integers not typed values. Type Duration make it look like a physical value but for division operation it is just a number.