duankangpazhuo0347 2013-04-17 04:03
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将XML属性解组到一个命名的嵌套结构中

Unmarshalling attributes from the current XML element into an anonymous struct works:

package main

import (
    "encoding/xml"
    "fmt"
)

type Attrs struct {
    Attr1 int `xml:"attr1,attr"`
    Attr2 int `xml:"attr2,attr"`
}
type Element struct {
    Attrs
}

func main() {
    data := `<element attr1="1" attr2="2"></element>`
    v := Element{}
    err := xml.Unmarshal([]byte(data), &v)
    if err != nil {
        fmt.Printf("error: %v", err)
        return
    }
    fmt.Printf("%#v
", v)
}

This prints main.Element{Attrs:main.Attrs{Attr1:1, Attr2:2}} as expected.

If the anonymous struct member is given a name, v.Attr1 and v.Attr2 are not unmarshalled.

type Element struct {
    AttrGroup Attrs
}

What's the correct tag to use on the struct member in this case?

Edit: Playground version

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1条回答 默认 最新

  • dongqiu9018 2013-04-17 11:04
    关注

    Why not just do this? I don't see what the named struct buys you other than complexity.

    (Playground)

    package main
    
    import (
        "encoding/xml"
        "fmt"
    )
    
    type Element struct {
        Attr1 int `xml:"attr1,attr"`
        Attr2 int `xml:"attr2,attr"`
    }
    
    func main() {
        data := `<element attr1="1" attr2="2"></element>`
        v := Element{}
        err := xml.Unmarshal([]byte(data), &v)
        if err != nil {
            fmt.Printf("error: %v", err)
            return
        }
        fmt.Printf("%#v
    ", v)
    }
    

    Which prints

    main.Element{Attr1:1, Attr2:2}
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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