如何创建重复的字母字符串？

Question

How do I create a bunch of alphabetic strings so that the first is "a", the 26th is "z", 27th is "aa"....e.g.:

a
b
c
d
...
...
...
x
y
z
aa
ab
ac
ad
...
...
...
ax
ay
az
aaa
aab
aac
...
...
...
aax
aay    
aaz
aaaa
aaab
...
...

I have the following playground code, but number 27 is "za" (s/b "aa"). I want to ultimately have the ability to create an infinite-length string w/ that pattern.

Answer 1

Below is a rewrite of your function that should do the trick. You'll note that is uses the fact that the letters A-Z have a sequential unicode numbering, meaning the alphabet does not have to be stored.

func NextAlias(last string) string {
    if last == "" {
        return "a"
    } else if last[len(last)-1] == 'z' {
        return last[:len(last)-1] + "aa"
    } else {
        return last[:len(last)-1] + string(last[len(last)-1] + 1)
    }
}

https://play.golang.org/p/Y2ViJKs_T4