douhe3313 2017-03-05 17:45
浏览 39
已采纳

克隆节点[golang.org/x/net/html]:堆栈溢出

I'm trying to clone/copy a html Node so that I can modify/duplicate it and then inject it back in the main document. The issue is that I'm getting a stack overflow[2]. I assume there is a race condition. It looks like it's due Parent and PrevSibling fields(based on my blind tests). Any idea why is that and how can I clone it completely(so that it can test positive on reflect.DeepEqual) ?

func clone(src *html.Node) *html.Node {
    if src == nil {
        return nil
    }
    n := html.Node{
        Parent:      clone(src.Parent),
        FirstChild:  clone(src.FirstChild),
        LastChild:   clone(src.LastChild),
        PrevSibling: clone(src.PrevSibling),
        NextSibling: clone(src.NextSibling),

        Type:      src.Type,
        DataAtom:  src.DataAtom,
        Data:      src.Data,
        Namespace: src.Namespace,
    }
    for _, v := range n.Attr {
        n.Attr = append(n.Attr, v)
    }
    return &n
}

[2]

runtime: goroutine stack exceeds 1000000000-byte limit
fatal error: stack overflow

runtime stack:
runtime.throw(0x3495b9, 0xe)
    /Users/x/gosrc/src/runtime/panic.go:566 +0x95
runtime.newstack()
    /Users/x/gosrc/src/runtime/stack.go:1061 +0x416
runtime.morestack()
    /Users/x/gosrc/src/runtime/asm_amd64.s:366 +0x7f

goroutine 7 [running]:
runtime.heapBitsSetType(0xc42a0ae5b0, 0x70, 0x68, 0x32e420)
    /Users/x/gosrc/src/runtime/mbitmap.go:867 fp=0xc4402002a8 sp=0xc4402002a0
runtime.mallocgc(0x70, 0x32e420, 0x1, 0x0)
    /Users/x/gosrc/src/runtime/malloc.go:690 +0x5ba fp=0xc440200348 sp=0xc4402002a8
runtime.newobject(0x32e420, 0x0)
    /Users/x/gosrc/src/runtime/malloc.go:785 +0x38 fp=0xc440200378 sp=0xc440200348
bitbucket.org/x/y/client.clone(0xc420138d20, 0x0)
  • 写回答

1条回答 默认 最新

  • dsplos5731 2017-03-05 18:06
    关注

    When deep-cloning a data structure containing pointers that is not a tree you need a more sophisticated approach; if you call

     n := Node{...
               next:clone(src.next),
               prev:clone(src.prev),
               ...}
    

    and your structure has even just two siblings nodes n1 and n2 where n1.next is &n2 and n2.prev is &n1 the code will stack overflow (cloning n1 will call clone(n2) for the next pointer that in turn will call clone(n1) for the prev pointer, looping back and forth forever until the call stack explodes).

    A solution is to keep a "cache" where when cloning a node you will store the src→cloned association, so the clone procedure will be able to return the node in case of recursive structures.

    What follows is a full minimal example:

    package main
    
    import "fmt"
    
    type Node struct {
        value      int
        prev, next *Node
    }
    
    func clone(n *Node, cache map[*Node]*Node) *Node {
        if n == nil {
            return nil
        }
    
        if val, ok := cache[n]; ok {
            return val
        }
    
        val := &Node{}
        cache[n] = val
        val.value = n.value
        val.prev = clone(n.prev, cache)
        val.next = clone(n.next, cache)
    
        return val
    }
    
    func printlist(n *Node) {
        for n != nil {
            println(fmt.Sprintf("address=%p, value=%v, prev=%p, next=%p",
                n, n.value, n.prev, n.next))
            n = n.next
        }
    }
    
    func main() {
        n1 := &Node{}
        n2 := &Node{}
        n3 := &Node{}
        n1.value = 100
        n2.value = 200
        n3.value = 300
        n1.next = n2
        n2.prev = n1
        n2.next = n3
        n3.prev = n2
    
        printlist(n1)
    
        println("Cloning list")
        c1 := clone(n1, make(map[*Node]*Node))
        printlist(c1)
    }
    

    Running this program on my machine i get

    ~/x$ go run recstruct.go
    address=0xc42000e540, value=100, prev=0x0, next=0xc42000e560
    address=0xc42000e560, value=200, prev=0xc42000e540, next=0xc42000e580
    address=0xc42000e580, value=300, prev=0xc42000e560, next=0x0
    Cloning list
    address=0xc42000e5c0, value=100, prev=0x0, next=0xc42000e5e0
    address=0xc42000e5e0, value=200, prev=0xc42000e5c0, next=0xc42000e600
    address=0xc42000e600, value=300, prev=0xc42000e5e0, next=0x0
    ~/x$ 
    

    where you can see that the three nodes have been cloned correctly and prev/next are pointing each other in the cloned structure list.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 如何让企业微信机器人实现消息汇总整合
  • ¥50 关于#ui#的问题:做yolov8的ui界面出现的问题
  • ¥15 如何用Python爬取各高校教师公开的教育和工作经历
  • ¥15 TLE9879QXA40 电机驱动
  • ¥20 对于工程问题的非线性数学模型进行线性化
  • ¥15 Mirare PLUS 进行密钥认证?(详解)
  • ¥15 物体双站RCS和其组成阵列后的双站RCS关系验证
  • ¥20 想用ollama做一个自己的AI数据库
  • ¥15 关于qualoth编辑及缝合服装领子的问题解决方案探寻
  • ¥15 请问怎么才能复现这样的图呀