如何为以下要匹配的字符串编写正则表达式模式

Question

I user golang func (*Regexp) Match to check if a string matches some pattern.

matched = regexp.Match(mystr, []byte(pattern))

How can I write pattern to get matched=true when passing mystr fulfilling the following requirements:

• contain at least one "/"
• not start with "alex/", "merry/", "david/"

so mystr="publicfile", "alex/personalfile", "merry/personalfile", "david/personalfile" will get rejected, which means matched=false.

How can I write one patter for this purpose? Thanks in advance.

Answer 1

Here is my approach: I reverse the requirements and obtain either false or true:

^(alex|merry|david)|^[^/]+$

The regex will match all strings starting with alex, merry or david OR all strings that do not contain /, and with ! operator we reverse the Match result:

var mystr = "alex/personalfile"
var pattern = regexp.MustCompile(`^(alex|merry|david)|^[^/]+$`) 
var matched = !pattern.Match([]byte(mystr))
fmt.Println(matched)

Result: false

See IDEONE demo