doujuanqi2909 2014-11-10 07:49
浏览 5
已采纳

转到模板检查当前页面的导航栏

I'm trying to set a li in a golang template to active based on the current page. From what I've read you can only do {{if .scoreheader}} to check existence of a variable. Is there another way around this?

    <div class="col-md-3">
      <ul class="nav nav-pills nav-stacked">

        {{range $id, $name := .test}}
            {{if $name == .scoreheader}}
            <li class="active">
            {{else}}
            <li>
            {{end}}
            <li><a href="/app/index/?company={{$id}}">{{$name}}</a></li>
        {{end}}
      </ul>
    </div>
  • 写回答

1条回答 默认 最新

  • 普通网友 2014-11-10 08:12
    关注

    You can use the eq function as explained in text/template:

    There is also a set of binary comparison operators defined as functions:

    eq Returns the boolean truth of arg1 == arg2

    So your if-statement would be:

    {{if eq $name $.scoreheader}}
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥500 52810做蓝牙接受端
  • ¥15 基于PLC的三轴机械手程序
  • ¥15 多址通信方式的抗噪声性能和系统容量对比
  • ¥15 winform的chart曲线生成时有凸起
  • ¥15 msix packaging tool打包问题
  • ¥15 finalshell节点的搭建代码和那个端口代码教程
  • ¥15 Centos / PETSc / PETGEM
  • ¥15 centos7.9 IPv6端口telnet和端口监控问题
  • ¥20 完全没有学习过GAN,看了CSDN的一篇文章,里面有代码但是完全不知道如何操作
  • ¥15 使用ue5插件narrative时如何切换关卡也保存叙事任务记录