doumin4553
2018-12-13 22:05
浏览 39
已采纳

如何始终从golang渠道获取最新价值?

I'm starting out with Go and I'm now writing a simple program which reads out data from a sensor and puts that into a channel to do some calculations with it. I now have it working as follows:

package main

import (
    "fmt"
    "time"
    "strconv"
)

func get_sensor_data(c chan float64) {
    time.Sleep(1 * time.Second)  // wait a second before sensor data starts pooring in
    c <- 2.1  // Sensor data starts being generated
    c <- 2.2
    c <- 2.3
    c <- 2.4
    c <- 2.5
}

func main() {

    s := 1.1

    c := make(chan float64)
    go get_sensor_data(c)

    for {
        select {
        case s = <-c:
            fmt.Println("the next value of s from the channel: " + strconv.FormatFloat(s, 'f', 1, 64))
        default:
            // no new values in the channel
        }
        fmt.Println(s)

        time.Sleep(500 * time.Millisecond)  // Do heavy "work"
    }
}

This works fine, but the sensor generates a lot of data, and I'm always only interested in the latest data. With this setup however, it only reads out the next item with every loop, which means that if the channel at some point contains 20 values, the newest value only is read out after 10 seconds.

Is there a way for a channel to always only contain one value at a time, so that I always only get the data I'm interested in, and no unnecessary memory is used by the channel (although the memory is the least of my worries)?

All tips are welcome!

3条回答 默认 最新

相关推荐 更多相似问题