Go函数去神秘化[重复]

Question

This question already has an answer here:

• Whats the difference of functions and methods in Go? 3 answers

Just got a basic Go question regarding this code:

type Ips []string
func (a Ips) Swap(i, j int) { a[i], a[j] = a[j], a[i] }

I believe (a Ips) is a parameter of Swap function, but why could it be not inside parenthesis?

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Answer 1

a Ips is the receiver of the method. Its parameters are i int and j int. This is a method bound to the Ips type that two strings in the array and returns nothing.

Try it on the playground