具有自己实现的处理程序的服务器未连续侦听

Question

I am trying to understand how to implement http.Handler, correctly. I wrote the barebone package code. Here is my package code

package app

import (
    "fmt"
    "net/http"
)

//Handler is the handler function
type Handler struct {
}

func (h *Handler) ServeHTTP(rw http.ResponseWriter, req *http.Request) {
    fmt.Println("Running ServeHTTP")
    rw.Write(([]byte)("Hello"))
    return
}

//NewHandler is
func NewHandler() *Handler {
    return &Handler{}
}

//Start will start the server
func (h *Handler) Start() {
    fmt.Println("Running Start")
    http.ListenAndServe("8080", h)

}

I made a directory in the abovementioned package named it "examples". I made a file main.go and wrote this in main function(After importing the Package).

func main() {

    handler := app.NewHandler()

    handler.Start()
}

But, when I run it with go run *.go, The Program abrupts almost instantly after writing Running Start on console. Shouldn't it listen continuouly. What am I doing wrong?

Answer 1

The http.ListenAndServe() func returns error. You could just check that by logging:

fmt.Println(http.ListenAndServe("8000", h))

and you will see that in your case its returning an error causing the function to return.

All you need to do is to pass address as :8000