douchui1488 2019-03-25 16:57
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百万分之一的Golang 1

I'm learning some Go and I'm doing some interview exercises. I have one exercice where one is asked to perform some operation randomly with a 1 in a million probability.

Let's say that I want to return true once in a million.

If my math is still right (and Google too), I would calculate this with the expression math.Pow(1-(1/1000000),1000000) however this keeps returning me 1 constantly, which doesn't seem correct.

Given this description, how could I ensure that I'd return true only once in a million? This sounds trivial but I'm really struggling with it.

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  • dpsq8476 2019-03-25 17:17
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    Go standard library has a rand package and it has Intn() function that will give you a pseudo-random number in the range of [0 , n). So to fire an event with probability of 1/1000000 you could do something like

    package main
    
    import (
        "fmt"
        "math/rand"
    )
    
    func main() {
        n := rand.Intn(1000000)
        if n == 154397 {
            fmt.Println("I am a lucky bastard!")
        } else {
            fmt.Println("I am not")
        }
    }
    

    Needless to say that 154397 could be replaced with any other integer in range. Link to playground

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