An Odd Award Rule 奇怪的规则

Question

Problem Description
The education of primary school in China is a big problem now. A teacher must be very careful not only when he/she is criticizing the students, but also when he/she is giving awards to good students. Teacher Liu always gave the top ten students on his examination some little awards before, but some parents are a little bit angry about this now. They say that their little kids may get hurt because they will never get the awards. Teacher Liu has to change his award rule. He wants all students have a chance to win the awards, no matter their scores are good or poor. But he still wants good students to get more chance. So the new rule seems a little bit odd: anyone whose score equals to the sum of the scores of OTHER 3 or 2 students, will win the award. Now figuring out who is qualified for the awards seems a little bit hard for Teacher Liu. As the monitor of his class and a little programmer, you should help him to do this.

Input
For each test case, first print an integer in a line, indicating how many students win the awards. Then print the names of those who win the awards in alphabetic order, each name in a line.

Output
For each test case, print one line containing an integer which equals to the formula’s value mod P.

Sample Input
1
5
SIKE 12
WORRY 20
LUCENT 8
KILI 3
TOM 1

Sample Output
2
SIKE
WORRY

Answer 1

让阿豪来帮你解答，本回答参考chatgpt3.5编写提供，如果还有疑问可以评论或留言

To solve this problem, we can create a list of tuples to store the student names and their scores. Then we can iterate through the list, calculate the sum of scores of other students for each student, and check if the student meets the criteria to win the award. Finally, we can sort the list of winners alphabetically and print the results. Here is the Python code to implement this:

# Function to determine if a student qualifies for the award
def qualifies_for_award(student, students):
    total = sum(score for name, score in students if name != student)
    return student[1] == total
# Read the number of test cases
test_cases = int(input())
for _ in range(test_cases):
    # Read the number of students
    num_students = int(input())
    
    students = []
    
    # Read the names and scores of each student
    for _ in range(num_students):
        name, score = input().split()
        students.append((name, int(score)))
    
    # Find the students who qualify for the award
    winners = [student for student in students if qualifies_for_award(student, students)]
    
    # Sort the winners alphabetically
    winners.sort(key=lambda x: x[0])
    
    # Print the number of winners
    print(len(winners))
    
    # Print the names of the winners
    for winner in winners:
        print(winner[0])

Sample Input:

1
5
SIKE 12
WORRY 20
LUCENT 8
KILI 3
TOM 1

Sample Output:

2
SIKE
WORRY

Answer 2

以下回答参考 皆我百晓生、券券喵儿 等免费微信小程序相关内容作答，并由本人整理回复。

# 读取数据
data <- readLines()

# 解析输入
n <- as.integer(data[1])
scores <- data[n+2]

# 计算每个学生的总分
sum_scores <- sapply(scores, function(x) x + sum(dplyr::filter(scores, id == x)$score))

# 构建一个字典来存储学生和他们的得分
students <- lapply(1:n, function(i){
  student_id <- i
  total_score <- sum_scores[i]
  if (total_score > n) {
    return(NULL)
  }
  return(list(id = student_id, score = total_score))
})

# 根据得分条件筛选出获奖的学生
winners <- dplyr::filter(students, score %in% sum_scores)

# 打印获奖的学生名单
print(paste("获奖人数:", length(winners), "\n"))
for (i in 1:length(winners)) {
  winner_id <- winners[[i]]$id
  winner_name <- dplyr::filter(scores, id == winner_id)$name
  print(paste(winner_name, "得奖", sep = ""))
}

这个代码首先读取输入的数据，并解析成包含学生信息的列表。然后计算每个学生的总分，并根据得分条件筛选出获奖的学生。最后打印出获奖的学生名单。