AJAX jQuery和PHP问题

Question

What I'm looking is that when the button is clicked then the values are taken and put into variables. The variables are then used in the AJAX call, so I can post them.

function addTask(){
  $("#add_task_button").click(function(){
    var task_title = $('#add_task_title').val();
    var task_description = $('#add_task_desc').val();
    var task_member = $( "#task_member option:selected" ).text();
    var task_status = $( "#task_status option:selected" ).text();

    $.ajax({
        url: '../php_scripts/add_task.php',
        type: 'POST',
        data: {'title': task_title, 'description': task_description, 'member': task_member, 'status': task_status},
        success: function() {
          alert("SUCCESS");
        },
        error: function(jqXHR,textStatus,errorThrown) {
          alert("FAILURE");
        }
    });
  });
}

This is the jQuery and AJAX call

<?php
 require_once "cdbconnect.php";

$taskTitle = $_POST['title'];
$taskDescription = $_POST['description'];
$memberName = $_POST['member'];
$groupName = "test";
$status = $_POST['status'];


 $query = "INSERT INTO task_tbl (Task_title, Task_description, Member_Name, Group_Name, Status) values('$taskTitle', '$taskDescription', '$memberName', '$groupName', '$status')";
 $result = $conn -> query($query);
 if(!$result)
   {
     $conn -> error;
   }

 mysqli_close($conn);
?>

This Is the PHP file. I always receive the failure alert as the data is not submitted to the table.

Am I missing something here?

Answer 1

A failing ajax request does not mean there is a logical error in your php script, but rather that the request could not be executed in the first place. Think "Server could not be reached", so your php code wasn't even executed.
Possible reasons are:

• Network problems
• Wrong url

In your case the url looks suspicious...