旧行李 2015-12-01 08:51 采纳率: 25%
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Ajax界面,然后没有

I want to package a ajax call into an interface without then.

If i do like this, it will just return 'No ajax return';

var ajaxReturn = ajaxFunction();
function ajaxFunction(){
    var text = 'No ajax return';
    // get fileName using an ajax get
    $.ajax();
    return text;
}

If i do like this, it will be ugly for using then;

function ajaxFunction(){
    var text = 'No ajax';
    var dtd = $.Deferred();
    $.ajax();
    return dtd.promise();
}

$.when(ajaxFunction()).then();

I just want the interface to be simple and return the right thing, can i?

//return the right
var ajaxReturn = ajaxFunction();
  • 写回答

3条回答 默认 最新

  • weixin_33711641 2015-12-01 09:02
    关注

    Well..., ajax is asynchronous so you either use .then() or use a callback logic... Doing synchronous ajax is not a option for me, so I won't even mention it.

    The alternative to .then() would be something like this:

    ajaxFunction(function(res){ // pass a function into it
        // this will be called when the ajax is done
        alert(res);
    });
    function ajaxFunction(callback){
        // get fileName using an ajax get
        $.ajax({
            success: callback
        });
    }
    

    But again, maybe you can use just a normal ajax callback pattern anyway

    $.ajax({
        ...
        success: function(res){
            // use the res
        }
    });
    
    评论

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