hxn_217 2013-01-28 05:22 采纳率: 0%
浏览 3576
已采纳

什么错误会使应用程序崩溃呢?

当我点击应用程序的logo,闪屏后,就会从intent中调用的第一个类。但是当tab加载后, onPreExecute() 一旦执行,应用程序就奔溃了。

public class HomeActivity extends Activity{
    private static final String dialog = null;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.user_main_tab_home);

        new HomeDownloadPage().execute();
    }

    public class HomeDownloadPage extends AsyncTask<String,Void,String>{

        private final ProgressDialog dialog = new ProgressDialog(HomeActivity.this);

         protected void onPreExecute() {
             this.dialog.setMessage("Have Paitence! ");
               this.dialog.show();

          }
         @Override
            protected String doInBackground(String... params) {

                User user = null;

                 try {

                        user = new User("4eeb");
                        user.getList();

                        /*
                         * Custom adapter
                         * */
                        ArrayList<User> users = new ArrayList<User>();

                        for(User u : user.following){
                            users.add(u);
                        }

                        ListView lv = (ListView) findViewById(R.id.user_list);

                        final UserFollowingListAdapter csl = new UserFollowingListAdapter(HomeActivity.this,R.layout.user_list,users,this);


                        OnItemClickListener listener = new OnItemClickListener() {

                            public void onItemClick(AdapterView<?> parent, View view, int position,long id) {

                            Object o = csl.getItem(position);

                           setTitle(parent.getItemAtPosition(position).toString());
                            }
                          };

                          lv.setAdapter(csl);


                          lv.setOnItemClickListener(listener);

                          /*
                           * Onclick listener
                           * */     
                          lv.setOnItemClickListener(new OnItemClickListener() {
                                        @Override
                                        public void onItemClick(AdapterView<?> parent, View view,int position, long id) {
                                            Intent i = new Intent("com.list.SEARCH");
                                            Toast.makeText(HomeActivity.this, "rowitem clicked", Toast.LENGTH_LONG).show();
                                            // TODO Auto-generated method stub

                                        }
                                    });

                        } catch (Exception e) {

                                showError();
                        }
                return null;
            }

         protected void onPostExecute(String result) {
                // execution of result of Long time consuming operation

              }

    }

                    public void showError(){
                    new AlertDialog.Builder(HomeActivity.this)
                    .setTitle(" Oops , Server down :( ")
                    .setPositiveButton("Ok", new DialogInterface.OnClickListener() {

                        @Override
                        public void onClick(DialogInterface arg0, int arg1) {
                            // TODO Auto-generated method stub

                        }
                        //
                    }).setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int whichButton) {
                            // Do nothing.
                        }
                    }).show();

                }

        }

在 doInBackground() 函数处得到错误。
确切的错误:

01-27 19:03:01.264: E/AndroidRuntime(1138): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()

问题出在哪呢?

  • 写回答

2条回答 默认 最新

  • yongyong_21 2013-01-29 02:11
    关注

    你正在试图实现的功能在一个后台线程中包括 UI(ListView lv = (ListView)

    findViewById(R.id.user_list);)
    

    你可以在后台处理信息,然后传回UI线程,更新UI.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 C++ yoloV5改写遇到的问题
  • ¥20 win11修改中文用户名路径
  • ¥15 win2012磁盘空间不足,c盘正常,d盘无法写入
  • ¥15 用土力学知识进行土坡稳定性分析与挡土墙设计
  • ¥70 PlayWright在Java上连接CDP关联本地Chrome启动失败,貌似是Windows端口转发问题
  • ¥15 帮我写一个c++工程
  • ¥30 Eclipse官网打不开,官网首页进不去,显示无法访问此页面,求解决方法
  • ¥15 关于smbclient 库的使用
  • ¥15 微信小程序协议怎么写
  • ¥15 c语言怎么用printf(“\b \b”)与getch()实现黑框里写入与删除?