这是配置文件user.hbm
`
<class name="com.entity.User" table="user">
<id name="email" column="email" type="string" length="100">
<generator class="assigned"></generator>
</id>
<property name="username" column="username" type="string"></property>
<property name="age" column="age" type="integer"></property>
<property name="sex" column="sex" type="integer"></property>
<set name="topic" cascade="all">
<key column="user_id" foreign-key="email"></key>
<one-to-many class="com.jiandan.entity.Topic" />
</set>
</class>`
这是topic类的配置文件
<class name="com.entity.Topic" table="topic">
<id column="id" name="id" type="string" length="100">
<generator class="uuid"></generator>
</id>
<property name="content" column="content" type="string"></property>
<property name="post_date" column="post_date" type="java.util.Date"></property>
<many-to-one class="com.jiandan.entity.User" name="user_id" column="user_id" ></many-to-one>
<set name="response" cascade="all">
<key column="topic_id"></key>
<one-to-many class="com.jiandan.entity.Response"/>
</set>
</class>
当我使用这种查询方式时就会出错：
Query query = session.createQuery("from Topic where user_id='Clement@gmail.com'");
List topic = query.list();
for(Topic t : topic){
System.out.println(t.getContent());
}
错误信息：
2013-10-7 16:34:24 org.hibernate.property.BasicPropertyAccessor$BasicSetter set
ERROR: HHH000123: IllegalArgumentException in class: com.jiandan.entity.Topic, setter method of property: user_id
2013-10-7 16:34:24 org.hibernate.property.BasicPropertyAccessor$BasicSetter set
ERROR: HHH000091: Expected type: java.lang.String, actual value: com.jiandan.entity.User_$$_javassist_0
Exception in thread "main" org.hibernate.PropertyAccessException: IllegalArgumentException occurred while calling setter of com.jiandan.entity.Topic.user_id
但是使用sql的方式却可以查出结果：
SQLQuery sql = session.createSQLQuery("select * from Topic where user_id = 'Clement@gmail.com'");
List<Object[]> topic = sql.list();
for(Object[] t : topic){
int len = t.length;
for(int i=0; i<len;i++){
System.out.println(t[i]);
}
}
谁能帮我解决这个问题，非常感谢！
